| Election Name: | 1826 New Hampshire gubernatorial election |
| Country: | New Hampshire |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1825 New Hampshire gubernatorial election |
| Previous Year: | 1825 |
| Next Election: | 1827 New Hampshire gubernatorial election |
| Next Year: | 1827 |
| Election Date: | 14 March 1826 |
| Nominee1: | David L. Morril |
| Party1: | Democratic-Republican |
| Popular Vote1: | 17,578 |
| Percentage1: | 58.08% |
| Nominee2: | Benjamin Pierce |
| Party2: | Democratic-Republican |
| Popular Vote2: | 12,287 |
| Percentage2: | 40.59% |
| Map Size: | 245px |
| Governor | |
| Before Election: | David L. Morril |
| Before Party: | Democratic-Republican |
| After Election: | David L. Morril |
| After Party: | Democratic-Republican |
The 1826 New Hampshire gubernatorial election was held on 14 March 1826 in order to elect the governor of New Hampshire. Incumbent Democratic-Republican governor David L. Morril defeated former Democratic-Republican member of the New Hampshire House of Representatives Benjamin Pierce.[1]
On election day, 14 March 1826, incumbent Democratic-Republican governor David L. Morril won re-election by a margin of 5,291 votes against his opponent Democratic-Republican candidate Benjamin Pierce, thereby retaining Democratic-Republican control over the office of governor. Morril was sworn in for his third term on 7 June 1826.[2]