1826 Maryland gubernatorial election explained

Election Name:1826 Maryland gubernatorial election
Country:Maryland
Type:Presidential
Ongoing:no
Previous Election:1824 Maryland gubernatorial election
Previous Year:1824
Next Election:1827 Maryland gubernatorial election
Next Year:1827
Election Date:2 January 1826
Nominee1:Joseph Kent
Party1:Democratic-Republican Party
Popular Vote1:59
Percentage1:65.56%
Nominee2:William Tyler
Popular Vote2:30
Percentage2:33.33
Governor
Before Election:Samuel Stevens Jr.
Before Party:Democratic-Republican Party
After Election:Joseph Kent
After Party:Democratic-Republican Party

The 1826 Maryland gubernatorial election was held on 2 January 1826 in order to elect the Governor of Maryland. Democratic-Republican nominee and incumbent member of the U.S. House of Representatives from Maryland's 2nd district Joseph Kent was elected by the Maryland General Assembly against candidates William Tyler and Thomas H. Carroll.[1]

General election

On election day, 2 January 1826, Democratic-Republican nominee Joseph Kent was elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Kent was sworn in as the 19th Governor of Maryland on 9 January 1826.[2]

Results

Notes and References

  1. Web site: Joseph Kent . 27 April 2024 . National Governors Association.
  2. Web site: MD Governor . ourcampaigns.com . 28 March 2005 . 27 April 2024.