See main article: 1824 United States presidential election.
| Election Name: | 1824 United States presidential election in Vermont |
| Country: | Vermont |
| Flag Year: | 1804 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1820 United States presidential election in Vermont |
| Previous Year: | 1820 |
| Next Election: | 1828 United States presidential election in Vermont |
| Next Year: | 1828 |
| Election Date: | October 26 – December 2, 1824 |
| Image1: | John Quincy Adams 1858 crop.jpg |
| Nominee1: | John Quincy Adams |
| Party1: | Democratic-Republican Party |
| Home State1: | Massachusetts |
| Running Mate1: | John C. Calhoun |
| Electoral Vote1: | 7 |
| President | |
| Before Election: | James Monroe |
| Before Party: | Democratic-Republican Party |
| After Election: | John Quincy Adams |
| After Party: | Democratic-Republican Party |
The 1824 United States presidential election in Vermont took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. The state legislature chose seven representatives, or electors (the last time they would do this in Vermont) to the Electoral College, who voted for President and Vice President.[1]
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Vermont cast seven electoral votes for New England native John Quincy Adams.
| 1824 United States presidential election in Vermont[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | John Quincy Adams | 7 | |||
| Democratic-Republican | Henry Clay | 0 | |||
| Democratic-Republican | William H. Crawford | 0 | |||
| Democratic-Republican | Andrew Jackson | 0 | |||
| Totals | 7 | ||||