1824 United States presidential election in Tennessee explained

See main article: 1824 United States presidential election.

Election Name:1824 United States presidential election in Tennessee
Type:presidential
Ongoing:no
Previous Election:1820 United States presidential election in Tennessee
Previous Year:1820
Next Election:1828 United States presidential election in Tennessee
Next Year:1828
Election Date:October 26 – December 2, 1824
Image1:Andrew Jackson.jpg
Nominee1:Andrew Jackson
Party1:Democratic-Republican Party
Home State1:Tennessee
Running Mate1:John C. Calhoun
Electoral Vote1:11
Popular Vote1:20,197
Percentage1:97.45%
Map Size:350px
President
Before Election:James Monroe
Before Party:Democratic-Republican Party
After Election:John Quincy Adams
After Party:Democratic-Republican Party
Colour1:698DC5

The 1824 United States presidential election in Tennessee took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 11 representatives, or electors, to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party and four different candidates from this party sought the Presidency. Tennessee voted for Andrew Jackson over William H. Crawford, John Quincy Adams, and Henry Clay. Jackson won Tennessee, his home state, by a wide margin of 95.94%.

Results

United States presidential election in Tennessee, 1824[1]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanAndrew Jackson20,19797.45%11
Democratic-RepublicanWilliam H. Crawford3121.51%0
Democratic-RepublicanJohn Quincy Adams2161.04%0
Totals20,725100.0%11

Notes and References

  1. Web site: 1824 Presidential General Election Results - Tennessee. U.S. Election Atlas. 27 February 2013.