See main article: 1824 United States presidential election.
Election Name: | 1824 United States presidential election in North Carolina |
Country: | North Carolina |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1820 United States presidential election in North Carolina |
Previous Year: | 1820 |
Next Election: | 1828 United States presidential election in North Carolina |
Next Year: | 1828 |
Election Date: | October 26 – December 2, 1824 |
Image1: | Andrew Jackson.jpg |
Nominee1: | Andrew Jackson |
Party1: | Democratic-Republican Party |
Home State1: | Tennessee |
Running Mate1: | John C. Calhoun |
Electoral Vote1: | 15 |
Popular Vote1: | 20,231 |
Percentage1: | 56.03% |
Nominee2: | William H. Crawford |
Party2: | Democratic-Republican Party |
Home State2: | Georgia |
Running Mate2: | Nathaniel Macon |
Electoral Vote2: | 0 |
Popular Vote2: | 15,622 |
Percentage2: | 43.26% |
President | |
Before Election: | James Monroe |
Before Party: | Democratic-Republican Party |
After Election: | John Quincy Adams |
After Party: | Democratic-Republican Party |
The 1824 United States presidential election in North Carolina took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. North Carolina voted for Andrew Jackson over William H. Crawford, Henry Clay, and John Quincy Adams. Jackson won North Carolina by a margin of 12.77%.
1824 United States presidential election in North Carolina[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Andrew Jackson | 20,231 | 56.03% | 15 | |
Democratic-Republican | William H. Crawford | 15,622 | 43.26% | 0 | |
N/A | Others | 256 | 0.71% | 0 | |
Totals | 36,109 | 100.0% | 15 | ||