See main article: 1824 United States presidential election.
Election Name: | 1824 United States presidential election in New Hampshire |
Country: | New Hampshire |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1820 United States presidential election in New Hampshire |
Previous Year: | 1820 |
Next Election: | 1828 United States presidential election in New Hampshire |
Next Year: | 1828 |
Election Date: | October 26 – December 2, 1824 |
Image1: | John Quincy Adams 1858 crop.jpg |
Nominee1: | John Quincy Adams |
Party1: | Democratic-Republican Party |
Home State1: | Massachusetts |
Running Mate1: | John C. Calhoun |
Electoral Vote1: | 8 |
Popular Vote1: | 9,389 |
Percentage1: | 93.59% |
Nominee2: | William H. Crawford |
Party2: | Democratic-Republican Party |
Home State2: | Georgia |
Running Mate2: | Nathaniel Macon |
Electoral Vote2: | 0 |
Popular Vote2: | 643 |
Percentage2: | 6.41% |
Map Size: | 150px |
President | |
Before Election: | James Monroe |
Before Party: | Democratic-Republican Party |
After Election: | John Quincy Adams |
After Party: | Democratic-Republican Party |
The 1824 United States presidential election in New Hampshire took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. New Hampshire voted for John Quincy Adams over William H. Crawford, Andrew Jackson, and Henry Clay. Adams won New Hampshire by a margin of 87.18%.
1824 United States presidential election in New Hampshire[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | John Quincy Adams | 9,389 | 93.59% | 8 | |
Democratic-Republican | William H. Crawford | 643 | 6.41% | 0 | |
Totals | 10,032 | 100.0% | 8 | ||