See main article: 1824 United States presidential election.
Election Name: | 1824 United States presidential election in Massachusetts |
Country: | Massachusetts |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1820 United States presidential election in Massachusetts |
Previous Year: | 1820 |
Next Election: | 1828 United States presidential election in Massachusetts |
Next Year: | 1828 |
Election Date: | October 26 – December 2, 1824 |
Turnout: | 29.0%[1] |
Image1: | John Quincy Adams by Gilbert Stuart, 1818.jpg |
Nominee1: | John Quincy Adams |
Party1: | Democratic-Republican Party |
Home State1: | Massachusetts |
Running Mate1: | John C. Calhoun |
Electoral Vote1: | 15 |
Popular Vote1: | 30,687 |
Percentage1: | 72.97% |
Nominee2: | Unpledged Massachusetts Electors |
Party2: | Democratic-Republican Party |
Home State2: | - |
Running Mate2: | - |
Electoral Vote2: | 0 |
Popular Vote2: | 6,616 |
Percentage2: | 15.73% |
President | |
Before Election: | James Monroe |
Before Party: | Democratic-Republican Party |
After Election: | John Quincy Adams |
After Party: | Democratic-Republican Party |
The 1824 United States presidential election in Massachusetts took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, the Democratic-Republican Party was the only major national party, and 4 different candidates from this party sought the Presidency. Massachusetts voted for native son John Quincy Adams.
1824 United States presidential election in Massachusetts[2] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | John Quincy Adams | 30,687 | 72.97% | 15 | |
Democratic-Republican | Unpledged electors | 6,616 | 15.73% | 0 | |
N/A | Others | 4,753 | 11.30% | 0 | |
Totals | 42,056 | 100.0% | 15 | ||