| Election Name: | 1824 New Hampshire gubernatorial election |
| Country: | New Hampshire |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1823 New Hampshire gubernatorial election |
| Previous Year: | 1823 |
| Next Election: | 1825 New Hampshire gubernatorial election |
| Next Year: | 1825 |
| Election Date: | 9 March 1824 |
| Nominee1: | David L. Morril |
| Party1: | Democratic-Republican |
| Popular Vote1: | 14,985 |
| Percentage1: | 49.19% |
| Nominee2: | Levi Woodbury |
| Party2: | Democratic-Republican |
| Popular Vote2: | 11,741 |
| Percentage2: | 38.54% |
| Nominee3: | Jeremiah Smith |
| Party3: | Federalist Party |
| Popular Vote3: | 3,300 |
| Percentage3: | 10.83% |
| Map Size: | 245px |
| Governor | |
| Before Election: | Levi Woodbury |
| Before Party: | Democratic-Republican |
| After Election: | David L. Morril |
| After Party: | Democratic-Republican |
The 1824 New Hampshire gubernatorial election was held on 9 March 1824 in order to elect the governor of New Hampshire. Former Democratic-Republican United States senator from New Hampshire David L. Morril defeated incumbent Democratic-Republican governor Levi Woodbury and former Federalist governor Jeremiah Smith. Since no candidate received a majority in the popular vote, Morril was elected by the New Hampshire General Court per the state constitution.[1]
On election day, 9 March 1824, Democratic-Republican candidate David L. Morril won the popular vote by a margin of 3,244 votes against his foremost opponent and incumbent Democratic-Republican governor Levi Woodbury. But since no candidate received a majority of the popular vote, a separate election was held by the New Hampshire General Court, which chose Morril as the winner, thereby retaining Democratic-Republican control over the office of governor. Morril was sworn in as the 10th governor of New Hampshire on 2 June 1824.[2]