See main article: 1820 United States presidential election.
Election Name: | 1820 United States presidential election in Rhode Island |
Country: | Rhode Island |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1816 United States presidential election in Rhode Island |
Previous Year: | 1816 |
Next Election: | 1824 United States presidential election in Rhode Island |
Next Year: | 1824 |
Election Date: | 1 November – 6 December 1820 |
Image1: | James Monroe White House portrait 1819.jpg |
Nominee1: | James Monroe |
Party1: | Democratic-Republican Party (United States) |
Home State1: | Virginia |
Running Mate1: | Daniel D. Tompkins |
Electoral Vote1: | 4 |
Popular Vote1: | 724 |
Percentage1: | 100.00% |
Map Size: | 250px |
The 1820 United States presidential election in Rhode Island took place between 1 November and 6 December 1820, as part of the 1820 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.[1]
Rhode Island cast four electoral votes for the Democratic-Republican candidate and incumbent President James Monroe, as he ran effectively unopposed. The electoral votes for Vice president were cast for Monroe's running mate Daniel D. Tompkins from New York. Each state elector was chosen by the voters statewide.[2]
1820 United States presidential election in Rhode Island[3] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | James Monroe (incumbent) | 724 | 100.0% | 4 | |
Totals | 724 | 100.0% | 4 | ||