1820 United States presidential election in Rhode Island explained

See main article: 1820 United States presidential election.

Election Name:1820 United States presidential election in Rhode Island
Country:Rhode Island
Type:presidential
Ongoing:no
Previous Election:1816 United States presidential election in Rhode Island
Previous Year:1816
Next Election:1824 United States presidential election in Rhode Island
Next Year:1824
Election Date:1 November – 6 December 1820
Image1:James Monroe White House portrait 1819.jpg
Nominee1:James Monroe
Party1:Democratic-Republican Party (United States)
Home State1:Virginia
Running Mate1:Daniel D. Tompkins
Electoral Vote1:4
Popular Vote1:724
Percentage1:100.00%
Map Size:250px

The 1820 United States presidential election in Rhode Island took place between 1 November and 6 December 1820, as part of the 1820 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

Rhode Island cast four electoral votes for the Democratic-Republican candidate and incumbent President James Monroe, as he ran effectively unopposed. The electoral votes for Vice president were cast for Monroe's running mate Daniel D. Tompkins from New York. Each state elector was chosen by the voters statewide.[2]

Results

1820 United States presidential election in Rhode Island[3]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanJames Monroe (incumbent)724100.0%4
Totals724100.0%4

See also

Notes and References

  1. Web site: A New Nation Votes. elections.lib.tufts.edu. 9 July 2023.
  2. Web site: 1820 Presidential General Election Results. U.S. Election Atlas. 9 July 2023.
  3. Web site: 1820 Presidential Election. 270towin.com. 9 July 2023.