1820 United States presidential election in Pennsylvania explained

See main article: 1820 United States presidential election.

Election Name:1820 United States presidential election in Pennsylvania
Country:Pennsylvania
Type:presidential
Ongoing:no
Previous Election:1816 United States presidential election in Pennsylvania
Previous Year:1816
Next Election:1824 United States presidential election in Pennsylvania
Next Year:1824
Election Date:November 1 – December 6, 1820
Nominee1:James Monroe
Party1:Democratic-Republican Party
Home State1:Virginia
Running Mate1:Daniel D. Tompkins
Electoral Vote1:24
Popular Vote1:30,313
Percentage1:94.12%
Nominee2:DeWitt Clinton
Party2:Independent (politician)
Home State2:New York
Running Mate2:-
Electoral Vote2:0
Popular Vote2:1,893
Percentage2:5.88%
Map Size:300px
President
Before Election:James Monroe
Before Party:Democratic-Republican Party
After Election:James Monroe
After Party:Democratic-Republican Party

The 1820 United States presidential election in Pennsylvania took place as part of the 1820 United States presidential election. Voters chose 25 representatives, or electors to the Electoral College, who voted for President and Vice President. Only 24 electoral votes were cast from Pennsylvania, however, due to one of the electors having died.[1]

During this election, James Monroe was re-elected by a large margin. Pennsylvania voted for Monroe over opposition candidate DeWitt Clinton.

Results

1820 United States presidential election in Pennsylvania[2]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanJames Monroe (incumbent)30,31394.12%24
IndependentDeWitt Clinton1,8935.88%0
Totals32,206100.0%24
Note: Election results totals only include known numbers, as verified by the source. Vote totals from several counties are missing/unknown.

See also

Notes and References

  1. Web site: 1820 ELECTION FOR THE NINTH TERM, 1821-1825. National Archives. 4 August 2012.
  2. Web site: Pennsylvania Presidential Election Returns 1820. Wilkes University. 4 August 2012.