See main article: 1820 United States presidential election.
Election Name: | 1820 United States presidential election in Ohio |
Country: | Ohio |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1816 United States presidential election in Ohio |
Previous Year: | 1816 |
Next Election: | 1824 United States presidential election in Ohio |
Next Year: | 1824 |
Election Date: | November 1 – December 6, 1820 |
Nominee1: | James Monroe |
Party1: | Democratic-Republican Party |
Home State1: | Virginia |
Running Mate1: | Daniel D. Tompkins |
Electoral Vote1: | 8 |
Popular Vote1: | 7,164 |
Percentage1: | 76.38% |
Nominee2: | John Quincy Adams |
Party2: | Democratic-Republican Party |
Home State2: | Massachusetts |
Electoral Vote2: | 0 |
Popular Vote2: | 2,215 |
Percentage2: | 23.62% |
President | |
Before Election: | James Monroe |
Before Party: | Democratic-Republican Party |
After Election: | James Monroe |
After Party: | Democratic-Republican Party |
The 1820 United States presidential election in Ohio took place between November 1 and December 6, 1820, as part of the 1820 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio re-elected incumbent Democratic-Republican Party President James Monroe by a large margin. Although Monroe ran unopposed, John Quincy Adams received a minority of the vote as an opposition candidate. This is the most recent time a party won every county in the state.
1820 United States presidential election in Ohio[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | James Monroe (incumbent) | 7,164 | 76.38% | 8 | |
Democratic-Republican | John Quincy Adams | 2,215 | 23.62% | 0 | |