See main article: 1820 United States presidential election.
| Election Name: | 1820 United States presidential election in New Jersey |
| Country: | New Jersey |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1816 United States presidential election in New Jersey |
| Previous Year: | 1816 |
| Next Election: | 1824 United States presidential election in New Jersey |
| Next Year: | 1824 |
| Election Date: | November 1 – December 6, 1820 |
| Nominee1: | James Monroe |
| Party1: | Democratic-Republican Party |
| Home State1: | Virginia |
| Running Mate1: | Daniel D. Tompkins |
| Electoral Vote1: | 8 |
| Popular Vote1: | 4,102 |
| Percentage1: | 99.88% |
| President | |
| Before Election: | James Monroe |
| Before Party: | Democratic-Republican Party |
| After Election: | James Monroe |
| After Party: | Democratic-Republican Party |
The 1820 United States presidential election in New Jersey took place between November 1 to December 6, 1820, as part of the 1820 United States presidential election. The state legislature chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, New Jersey cast its eight electoral votes to Democratic Republican candidate and incumbent President James Monroe.
Effectively, the 1820 presidential election was an election with no campaign, since there was no serious opposition to Monroe and Tompkins. In fact, they won all the electoral votes barring one from New Hampshire, which was cast for Secretary of State John Quincy Adams.[1]