See main article: 1820 United States presidential election.
| Election Name: | 1820 United States presidential election in Maine |
| Country: | Maine |
| Flag Year: | 1804 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1816 United States presidential election in Massachusetts |
| Previous Year: | 1816 (Mass.) |
| Next Election: | 1824 United States presidential election in Maine |
| Next Year: | 1824 |
| Election Date: | November 1 – December 6, 1820 |
| Image1: | James Monroe White House portrait 1819.jpg |
| Nominee1: | James Monroe |
| Party1: | Democratic-Republican Party |
| Alliance1: | – |
| Home State1: | Virginia |
| Running Mate1: | Daniel D. Tompkins |
| Electoral Vote1: | 9 |
| Popular Vote1: | 9,282 |
| Percentage1: | 95.83% |
| President | |
| Before Election: | James Monroe |
| Before Party: | Democratic-Republican Party |
| After Election: | James Monroe |
| After Party: | Democratic-Republican Party |
The 1820 United States presidential election in Maine took place between November 1 to December 6, 1820, as part of the 1820 United States presidential election. The state's popular vote chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.[1]
Maine would vote in its first ever United States presidential election, having become the 23rd state by splitting off Massachusetts on March 15 of the same year. The state would cast its nine electoral votes to Democratic Republican candidate and incumbent President James Monroe, who would win the state by a margin of 91.56%.
Effectively, the 1820 presidential election was an election with no campaign, since there was no serious opposition to Monroe and Tompkins. In fact, Monroe won all the electoral votes barring one from neighboring New Hampshire, which was cast for Secretary of State John Quincy Adams.