1820 United States presidential election in Georgia explained

See main article: 1820 United States presidential election.

Election Name:1820 United States presidential election in Georgia
Country:Georgia (U.S. state)
Type:presidential
Ongoing:no
Previous Election:1816 United States presidential election in Georgia
Previous Year:1816
Next Election:1824 United States presidential election in Georgia
Next Year:1824
Election Date:1 November – 6 December 1820
Image1:James Monroe White House portrait 1819.jpg
Nominee1:James Monroe
Party1:Democratic-Republican Party (United States)
Home State1:Virginia
Running Mate1:Daniel D. Tompkins
Electoral Vote1:8

The 1820 United States presidential election in Georgia took place between 1 November and 6 December 1820, as part of the 1820 United States presidential election. The state legislature chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia cast eight electoral votes for the Democratic-Republican candidate and incumbent President James Monroe, as he ran effectively unopposed. The electoral votes for Vice president were cast for Monroe's running mate Daniel D. Tompkins from New York. These electors were elected by the Georgia General Assembly, the state legislature, rather than by popular vote.[1]

Results

1820 United States presidential election in Georgia[2]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanJames Monroe (incumbent)8
Totals8

See also

Notes and References

  1. Web site: 1820 Presidential General Election Results. U.S. Election Atlas. 9 July 2023.
  2. Web site: 1820 Presidential Election. 270towin.com. 9 July 2023.