1820 United States presidential election in Delaware explained

See main article: 1820 United States presidential election.

Election Name:1820 United States presidential election in Delaware
Country:Delaware
Type:presidential
Ongoing:no
Previous Election:1816 United States presidential election in Delaware
Previous Year:1816
Next Election:1824 United States presidential election in Delaware
Next Year:1824
Election Date:1 November – 6 December 1820
Image1:James Monroe White House portrait 1819.jpg
Nominee1:James Monroe
Party1:Democratic-Republican Party (United States)
Home State1:Virginia
Running Mate1:Daniel D. Tompkins
Electoral Vote1:4

The 1820 United States presidential election in Delaware took place between 1 November and 6 December 1820, as part of the 1820 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware cast four electoral votes for the Democratic-Republican candidate and incumbent President James Monroe, as he ran effectively unopposed. The electoral votes for Vice president were however not cast for Monroe's running mate Daniel D. Tompkins, but for Federalist Daniel Rodney from Delaware. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote.[1]

Results

1820 United States presidential election in Delaware[2]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanJames Monroe (incumbent)4
Totals4

See also

Notes and References

  1. Web site: 1820 Presidential General Election Results. U.S. Election Atlas. 8 July 2023.
  2. Web site: 1820 Presidential Election. 270towin.com. 8 July 2023.