See main article: 1816 United States presidential election.
Election Name: | 1816 United States presidential election in Rhode Island |
Country: | Rhode Island |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1812 United States presidential election in Rhode Island |
Previous Year: | 1812 |
Next Election: | 1820 United States presidential election in Rhode Island |
Next Year: | 1820 |
Election Date: | November 1 – December 4, 1816 |
Image1: | John Vanderlyn - James Monroe - Google Art Project.jpg |
Nominee1: | James Monroe |
Party1: | Democratic-Republican Party |
Home State1: | Virginia |
Running Mate1: | Daniel D. Tompkins |
Electoral Vote1: | 4 |
Popular Vote1: | 1,236 |
Percentage1: | 100.00% |
President | |
Before Election: | James Madison |
Before Party: | Democratic-Republican Party |
After Election: | James Monroe |
After Party: | Democratic-Republican Party |
Flag Year: | 1816 |
The 1816 United States presidential election in Rhode Island took place as part of the 1816 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.
Rhode Island voted for the Democratic-Republican candidate, James Monroe. Monroe won Rhode Island by a margin of 100.00%. Because the Federalist challenger in the nation, Rufus King, was not on the ballot.
1816 United States presidential election in Rhode Island[1] | ||||||
---|---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | ||
Democratic-Republican | James Monroe | 1,236 | 100.00% | 4 | ||
Federalist | Rufus King (not on ballot) | — | — | 0 | ||
Totals | 1,236 | 100.0% | 4 |