See main article: 1816 United States presidential election.
| Election Name: | 1816 United States presidential election in Kentucky |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1812 United States presidential election in Kentucky |
| Previous Year: | 1812 |
| Next Election: | 1820 United States presidential election in Kentucky |
| Next Year: | 1820 |
| Election Date: | 1 November – 4 December 1816 |
| Image1: | James Monroe White House portrait 1819.jpg |
| Nominee1: | James Monroe |
| Party1: | Democratic-Republican Party (United States) |
| Home State1: | Virginia |
| Running Mate1: | Daniel D. Tompkins |
| Electoral Vote1: | 12 |
| Popular Vote1: | 1,864 |
| Percentage1: | 100.0% |
The 1816 United States presidential election in Kentucky took place between 1 November and 4 December 1816, as part of the 1816 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.[1]
Kentucky cast twelve electoral votes for the Democratic-Republican candidate James Monroe over the Federalist candidate Rufus King. The electoral votes for Vice president were cast for Monroe's running mate Daniel D. Tompkins from New York. The state was divided into three electoral districts with four electors each, whereupon each district's voters chose the electors.[2]
| 1816 United States presidential election in Kentucky[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Monroe | 1,864 | 100.0% | 12 | |
| Federalist | Rufus King | 0 | 0.00% | 0 | |
| Totals | 1,864 | 100.0% | 12 | ||