1816 United States presidential election in Georgia explained

See main article: 1816 United States presidential election.

Election Name:1816 United States presidential election in Georgia
Country:Georgia (U.S. state)
Type:presidential
Ongoing:no
Previous Election:1812 United States presidential election in Georgia
Previous Year:1812
Next Election:1820 United States presidential election in Georgia
Next Year:1820
Election Date:1 November – 4 December 1816
Image1:John Vanderlyn - James Monroe - Google Art Project.jpg
Nominee1:James Monroe
Party1:Democratic-Republican Party (United States)
Home State1:Virginia
Running Mate1:Daniel D. Tompkins
Electoral Vote1:8
Nominee2:Rufus King
Party2:Federalist Party (United States)
Home State2:New York
Running Mate2:John E. Howard
Electoral Vote2:0

The 1816 United States presidential election in Georgia took place between 1 November and 4 December 1816, as part of the 1816 United States presidential election. The state legislature chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia cast eight electoral votes for the Democratic-Republican candidate James Monroe over the Federalist candidate Rufus King. The electoral votes for Vice president were cast for Monroe's running mate Daniel D. Tompkins from New York. These electors were elected by the Georgia General Assembly, the state legislature, rather than by popular vote.[1]

Results

1816 United States presidential election in Georgia[2]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanJames Monroe8
FederalistRufus King0
Totals8

See also

Notes and References

  1. Web site: 1816 Presidential General Election Results. U.S. Election Atlas. 10 July 2023.
  2. Web site: 1816 Presidential Election. 270towin.com. 10 July 2023.