| Election Name: | 1816 Ohio gubernatorial election |
| Country: | Ohio |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1814 Ohio gubernatorial election |
| Previous Year: | 1814 |
| Next Election: | 1818 Ohio gubernatorial election |
| Next Year: | 1818 |
| Election Date: | 8 October 1816 |
| Nominee1: | Thomas Worthington |
| Party1: | Democratic-Republican Party |
| Popular Vote1: | 22,931 |
| Percentage1: | 74.35% |
| Nominee2: | James Dunlap |
| Party2: | Democratic-Republican Party |
| Popular Vote2: | 6,295 |
| Percentage2: | 20.41% |
| Nominee3: | Ethan Allen Brown |
| Party3: | Democratic-Republican Party |
| Popular Vote3: | 1,607 |
| Percentage3: | 5.21% |
| Governor | |
| Before Election: | Thomas Worthington |
| Before Party: | Democratic-Republican Party |
| After Election: | Thomas Worthington |
| After Party: | Democratic-Republican Party |
The 1816 Ohio gubernatorial election was held on 8 October 1816 in order to elect the Governor of Ohio. Incumbent Democratic-Republican Governor of Ohio Thomas Worthington defeated fellow Democratic-Republican members James Dunlap and Ethan Allen Brown.
On election day, 8 October 1816, Democratic-Republican nominee Thomas Worthington won re-election by a margin of 16,636 votes against his opponents and fellow Democratic-Republican members James Dunlap and Ethan Allen Brown, thereby retaining Democratic-Republican control over the office of Governor. Worthington was sworn in for his second term on 9 December 1816.[1]