See main article: 1808 United States presidential election.
| Election Name: | 1808 United States presidential election in Rhode Island |
| Country: | Rhode Island |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1804 United States presidential election in Rhode Island |
| Previous Year: | 1804 |
| Next Election: | 1812 United States presidential election in Rhode Island |
| Next Year: | 1812 |
| Election Date: | November 4 – December 7, 1808 |
| Image1: | CharlesCPinckney (cropped).png |
| Percentage1: | 53.30% |
| Nominee1: | Charles C. Pinckney |
| Party1: | Federalist Party |
| Home State1: | South Carolina |
| Running Mate1: | Rufus King |
| Electoral Vote1: | 4 |
| Popular Vote1: | 3,072 |
| Nominee2: | James Madison |
| Percentage2: | 46.70% |
| Popular Vote2: | 2,692 |
| Electoral Vote2: | 0 |
| Running Mate2: | George Clinton |
| Home State2: | Virginia |
| Party2: | Democratic-Republican Party |
| Map Size: | 230px |
| President | |
| Before Election: | Thomas Jefferson |
| Before Party: | Democratic-Republican Party |
| After Election: | James Madison |
| After Party: | Democratic-Republican Party |
The 1808 United States presidential election in Rhode Island took place as part of the 1808 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.
Rhode Island voted for the Federalist candidate, Charles C. Pinckney, over the Democratic-Republican candidate, James Madison. Pinckney won Rhode Island by a margin of 53.30%.
| 1808 United States presidential election in New Hampshire[1] | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | ||
| Federalist | Charles C. Pinckney | 3,072 | 53.30% | 4 | ||
| Democratic-Republican | James Madison | 2,692 | 46.70% | – | ||
| Totals | 5,764 | 100.00% | 4 | |||