See main article: 1808 United States presidential election.
Election Name: | 1808 United States presidential election in New York |
Country: | New York |
Flag Year: | 1778 |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1804 United States presidential election in New York |
Previous Year: | 1804 |
Next Election: | 1812 United States presidential election in New York |
Next Year: | 1812 |
Election Date: | November 4 – December 7, 1808 |
Image1: | James Madison.jpg |
Nominee1: | James Madison |
Party1: | Democratic-Republican Party |
Home State1: | Virginia |
Running Mate1: | George Clinton |
Electoral Vote1: | 13 |
Percentage1: | 68.38% |
Nominee2: | George Clinton |
Party2: | Democratic-Republican Party |
Home State2: | New York |
Running Mate2: | James Madison/ James Monroe |
Electoral Vote2: | 6 |
Percentage2: | 31.62% |
President | |
Before Election: | Thomas Jefferson |
Before Party: | Democratic-Republican Party |
After Election: | James Madison |
After Party: | Democratic-Republican Party |
The 1808 United States presidential election in New York took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. The state legislature chose 19 representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, New York split its 19 electoral votes among two Democratic-Republican candidates. 13 electoral votes went to Secretary of State James Madison while the remaining 6 went to incumbent Vice President George Clinton. Clinton was also supported by a group of New York Democratic-Republicans for president even though he had remained the party's official vice presidential candidate.[1]
This would be the final election until 1972 in which New York did not have the largest number of electors in the Electoral College.