See main article: 1808 United States presidential election.
Election Name: | 1808 United States presidential election in New Jersey |
Country: | New Jersey |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1804 United States presidential election in New Jersey |
Previous Year: | 1804 |
Next Election: | 1812 United States presidential election in New Jersey |
Next Year: | 1812 |
Election Date: | November 4 - December 7, 1808 |
Image1: | James Madison.jpg |
Percentage1: | 55.97% |
Nominee1: | James Madison |
Party1: | Democratic-Republican Party |
Home State1: | Virginia |
Running Mate1: | George Clinton |
Electoral Vote1: | 8 |
Popular Vote1: | 18,670 |
Nominee2: | Charles C. Pinckney |
Percentage2: | 44.03% |
Popular Vote2: | 14,687 |
Electoral Vote2: | 0 |
Running Mate2: | Rufus King |
Home State2: | South Carolina |
Party2: | Federalist Party (United States) |
Map Size: | 230px |
President | |
Before Election: | Thomas Jefferson |
Before Party: | Democratic-Republican Party |
After Election: | James Madison |
After Party: | Democratic-Republican Party |
The 1808 United States presidential election in New Jersey took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. The state chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, New Jersey cast its eight electoral votes to Democratic Republican candidate and Secretary of State James Madison.[1]