See main article: 1808 United States presidential election.
| Election Name: | 1808 United States presidential election in Kentucky |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1804 United States presidential election in Kentucky |
| Previous Year: | 1804 |
| Next Election: | 1812 United States presidential election in Kentucky |
| Next Year: | 1812 |
| Election Date: | 4 November – 7 December 1808 |
| Image1: | James Madison.jpg |
| Nominee1: | James Madison |
| Party1: | Democratic-Republican Party (United States) |
| Home State1: | Virginia |
| Running Mate1: | George Clinton |
| Electoral Vote1: | 7 |
| Popular Vote1: | 2,679 |
| Percentage1: | 98.02% |
| Nominee2: | Charles C. Pinckney |
| Party2: | Federalist Party (United States) |
| Home State2: | South Carolina |
| Running Mate2: | Rufus King |
| Electoral Vote2: | 0 |
| Popular Vote2: | 54 |
| Percentage2: | 1.98% |
The 1808 United States presidential election in Kentucky took place between 4 November and 7 December 1808, as part of the 1808 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.[1]
Kentucky cast seven electoral votes, as one elector didn't vote, for the Democratic-Republican candidate James Madison over the Federalist candidate Charles C. Pinckney. The electoral votes for Vice president were cast for Madison's running mate George Clinton from New York. The state was divided into two electoral districts with four electors each, whereupon each district's voters chose the electors.[2]
| 1808 United States presidential election in Kentucky[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Madison | 2,679 | 98.02% | 7 | |
| Federalist | Charles C. Pinckney | 54 | 1.98% | 0 | |
| None | Not Cast | – | – | 1 | |
| Totals | 2,733 | 100.0% | 8 | ||