1807 United States Senate election in New York explained

The 1807 United States Senate election in New York was held on February 3, 1807, by the New York State Legislature to elect a United States Senator (Class 3) to represent the State of New York in the United States Senate.

Background

John Smith had been elected to this seat in February 1804, after the resignation of DeWitt Clinton, replacing the temporarily appointed John Armstrong. Smith took his seat on February 23, 1804, and his term would expire on March 3, 1807.

At the State election in April 1806, the Democratic-Republican Party (D-R) won a large majority to the Assembly (82 D-R and 18 Federalist), and all 9 State Senate seats up for election. The 30th New York State Legislature met from January 27 to April 7, 1807, at Albany, New York.

Candidates

The incumbent U.S. Senator John Smith ran for re-election as the candidate of the Democratic-Republican Party. At this time the Democratic-Republican Party was split in two factions: the "Lewisites" (allies of Governor Morgan Lewis), and the "Clintonians" (allies of Mayor of New York DeWitt Clinton). The Federalist Party which had no seats in the State Senate and only a small minority in the State Assembly was allied in State politics with the Lewisites, the smaller faction, thus forming a bloc large enough to outvote the Clintonians. Nevertheless, for the election of a U.S. Senator both Democratic-Republican factions united supporting Smith.

Result

The incumbent John Smith was re-elected.

1807 United States Senator election result
OfficeHouseDemocratic-RepublicanFederalist
U.S. SenatorState Senate (32 members)John Smith
State Assembly (100 members)John Smith

Aftermath

John Smith served until the end of the term on March 3, 1813.

Sources