See main article: 1804 United States presidential election.
Election Name: | 1804 United States presidential election in Virginia |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1800 United States presidential election in Virginia |
Previous Year: | 1800 |
Next Election: | 1808 United States presidential election in Virginia |
Next Year: | 1808 |
Election Date: | November 2 – December 5, 1804 |
Image1: | File:Thomas Jefferson by Rembrandt Peale, 1800.jpg |
Nominee1: | Thomas Jefferson |
Party1: | Democratic-Republican Party |
Home State1: | Virginia |
Electoral Vote1: | 24 |
Country: | Virginia |
Percentage1: | 99.42% |
President | |
Before Election: | Thomas Jefferson |
Before Party: | Democratic-Republican Party |
After Election: | Thomas Jefferson |
After Party: | Democratic-Republican Party |
Popular Vote1: | 12,926 |
The 1804 United States presidential election in Virginia took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. Virginia voters chose 25 representatives, or electors to the Electoral College, who voted for President and Vice President.
Incumbent Democratic-Republican President Thomas Jefferson won with an overwhelming majority of nearly 99.5%, as well as all electoral votes, making this state with the highest percentage of votes in the 1804 presidential election behind only Kentucky, New Jersey, and Rhode Island, and also the highest percentage ever in the state's presidential election history since George Washington's 1788-89 and 1792 records until in 1816.[1]
1804 United States presidential election in Virginia[2] | ||||||
---|---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | ||
Democratic-Republican | Thomas Jefferson | 12,926 | 99.42% | 24 | ||
Federalist | Charles C. Pinckney | 75 | 0.58% | 0 | ||
Totals | 13,001 | 100.00% | 24 |