1804 United States presidential election in New Hampshire explained

See main article: 1804 United States presidential election.

Election Name:1804 United States presidential election in New Hampshire
Country:New Hampshire
Type:presidential
Ongoing:no
Previous Election:1800 United States presidential election in New Hampshire
Previous Year:1800
Next Election:1808 United States presidential election in New Hampshire
Next Year:1808
Election Date:November 2 – December 5, 1804
Image1:Thomas Jefferson by Rembrandt Peale, 1800.jpg
Nominee1:Thomas Jefferson
Party1:Democratic-Republican Party (United States)
Home State1:Virginia
Running Mate1:George Clinton
Electoral Vote1:7
Popular Vote1:9,088
Percentage1:52.01%
Nominee2:Charles C. Pinckney
Party2:Federalist Party
Home State2:South Carolina
Running Mate2:Rufus King
Popular Vote2:8,386
Percentage2:47.99%
President
Before Election:Thomas Jefferson
Before Party:Democratic-Republican Party
After Election:Thomas Jefferson
After Party:Democratic-Republican Party

The 1804 United States presidential election in New Hampshire took place between November 2 to December 5, 1804, as part of the 1804 United States presidential election to elect the President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for incumbent Democratic-Republican President Thomas Jefferson over Federalist candidate and Minister to France Charles C. Pinckney by a margin of 4.02% of the popular vote.

Results

1804 United States presidential election in New Hampshire[1]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanThomas Jefferson (incumbent)9,08852.01%7
FederalistCharles C. Pinckney8,38647.99%
Totals17,474100.00%7

See also

References

  1. Web site: New Hampshire 1804 Electoral College . 2024-06-22 . A New Nation Votes.