See main article: 1800 United States presidential election.
| Election Name: | 1800 United States presidential election in Vermont |
| Country: | Vermont |
| Flag Image: | Flag of the Vermont Republic.svg |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1796 United States presidential election in Vermont |
| Previous Year: | 1796 |
| Next Election: | 1804 United States presidential election in Vermont |
| Next Year: | 1804 |
| Election Date: | October 31 - December 3, 1800 |
| Image1: | File:Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg |
| Nominee1: | John Adams |
| Party1: | Federalist Party (United States) |
| Home State1: | Massachusetts |
| Electoral Vote1: | 4 |
| Percentage1: | 100.00% |
| Nominee2: | Charles C. Pinckney |
| Party2: | Federalist Party |
| Home State2: | South Carolina |
| Electoral Vote2: | 4 |
| Percentage2: | - |
| President | |
| Before Election: | John Adams |
| Before Party: | Federalist Party (United States) |
| After Election: | Thomas Jefferson |
| After Party: | Democratic-Republican Party |
The 1800 United States presidential election in Vermont took place between October 31 and December 3, 1800, as part of the 1800 United States presidential election. The state legislature chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, Vermont cast four electoral votes for incumbent Federalist President and New England native John Adams.[1] However, Adams would lose to Democratic-Republican Party candidate Thomas Jefferson nationally.