See main article: 1800 United States presidential election.
| Election Name: | 1800 United States presidential election in New York |
| Country: | New York |
| Flag Year: | 1778 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1796 United States presidential election in New York |
| Previous Year: | 1796 |
| Next Election: | 1804 United States presidential election in New York |
| Next Year: | 1804 |
| Election Date: | October 31 – December 3, 1800 |
| Image1: | Thomas Jefferson by Rembrandt Peale, 1800.jpg |
| Nominee1: | Thomas Jefferson |
| Party1: | Democratic-Republican Party |
| Home State1: | Virginia |
| Running Mate1: | Aaron Burr |
| Electoral Vote1: | 12 |
| Percentage1: | 100.00% |
| President | |
| Before Election: | John Adams |
| Before Party: | Federalist Party (United States) |
| After Election: | Thomas Jefferson |
| After Party: | Democratic-Republican Party |
In the 1800 United States presidential election, electors could be selected in each state at any time after October 31 and all electors were required to vote on December 3, 1800. In the 1800 United States presidential election in New York The state legislature chose 12 representatives, or electors to the Electoral College on November 6, 1800. [1] Based on the constitutional provision in effect at that time electors cast two votes. The candidate receiving most votes would be President. The runner up would be elected Vice President.
During this election, New York cast 12 electoral votes for Democratic-Republican Party candidates Thomas Jefferson and Aaron Burr.[2]