See main article: 1800 United States presidential election.
| Election Name: | 1800 United States presidential election in Massachusetts |
| Country: | Massachusetts |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1796 United States presidential election in Massachusetts |
| Previous Year: | 1796 |
| Next Election: | 1804 United States presidential election in Massachusetts |
| Next Year: | 1804 |
| Election Date: | October 31 to December 3, 1800 |
| Image1: | File:Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg |
| Nominee1: | John Adams |
| Party1: | Federalist Party |
| Home State1: | Massachusetts |
| Electoral Vote1: | 16 |
| Percentage1: | 100% |
| Nominee2: | Charles C. Pinckney |
| Party2: | Federalist Party (United States) |
| Home State2: | South Carolina |
| Electoral Vote2: | 16 |
| Percentage2: | - |
| President | |
| Before Election: | John Adams |
| Before Party: | Federalist Party |
| After Election: | Thomas Jefferson |
| After Party: | Democratic-Republican Party |
The 1800 United States presidential election in Massachusetts took place between October 31 to December 3, 1800, as part of the 1800 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for president and Vice President.
During this election, John Adams and his running mate Charles C. Pinckney were the only two candidates on the ballot in Massachusetts.[1] As both represented the Federalist Party there was no popular vote. While Adams won all 16 Massachusetts state electors in his home state, it was not enough to win the general election. The Democratic-Republican Party candidate, Vice President Thomas Jefferson, defeated Adams.[2]