1800 United States presidential election in Kentucky explained

See main article: 1800 United States presidential election.

Election Name:1800 United States presidential election in Kentucky
Type:presidential
Ongoing:no
Previous Election:1796 United States presidential election in Kentucky
Previous Year:1796
Next Election:1804 United States presidential election in Kentucky
Next Year:1804
Election Date:31 October – 11 December 1800
Image1:Thomas Jefferson by Rembrandt Peale, 1800.jpg
Nominee1:Thomas Jefferson
Party1:Democratic-Republican Party (United States)
Home State1:Virginia
Running Mate1:Aaron Burr
Electoral Vote1:4
Popular Vote1:119
Percentage1:100.00%
Nominee2:John Adams
Party2:Federalist Party (United States)
Home State2:Massachusetts
Running Mate2:Charles C. Pinckney
Electoral Vote2:0
Popular Vote2:0
Percentage2:0.00%

The 1800 United States presidential election in Kentucky took place between 31 October and 3 December 1800, as part of the 1800 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

Kentucky cast four electoral votes for the Democratic-Republican candidate and incumbent Vice President Thomas Jefferson over the Federalist candidate and incumbent President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. The state was divided into two electoral districts with two electors each, whereupon each district's voters chose the electors.[2]

Results

1800 United States presidential election in Kentucky[3]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanThomas Jefferson119100.00%4
FederalistJohn Adams (incumbent)00.00%0
Totals119100.00%4

See also

Notes and References

  1. Web site: A New Nation Votes. 14 July 2023. elections.lib.tufts.edu.
  2. Web site: 1800 Presidential General Election Results. U.S. Election Atlas. 14 July 2023.
  3. Web site: 1800 Presidential Election. 270towin.com. 14 July 2023.