| Election Name: | 1799 Rhode Island gubernatorial election |
| Country: | Rhode Island |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1798 Rhode Island gubernatorial election |
| Previous Year: | 1798 |
| Next Election: | 1800 Rhode Island gubernatorial election |
| Next Year: | 1800 |
| Election Date: | 3 April 1799 |
| Nominee1: | Arthur Fenner |
| Party1: | Democratic-Republican Party |
| Percentage1: | 100.00% |
| Governor | |
| Before Election: | Arthur Fenner |
| Before Party: | Democratic-Republican Party |
| After Election: | Arthur Fenner |
| After Party: | Democratic-Republican Party |
The 1799 Rhode Island gubernatorial election was held on 3 April 1799 in order to elect the Governor of Rhode Island. Incumbent Democratic-Republican Governor Arthur Fenner won re-election as he ran unopposed. The exact number of votes cast in this election are unknown.[1]
On election day, 3 April 1799, incumbent Democratic-Republican Governor Arthur Fenner won re-election as he ran unopposed, thereby retaining Democratic-Republican control over the office of Governor. Fenner was sworn in for his tenth term on 5 May 1799.[2]