See main article: 1796 United States presidential election.
| Election Name: | 1796 United States presidential election in Rhode Island |
| Country: | Rhode Island |
| Flag Year: | 1796 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1792 United States presidential election in Rhode Island |
| Previous Year: | 1792 |
| Next Election: | 1800 United States presidential election in Rhode Island |
| Next Year: | 1800 |
| Election Date: | November 4 – December 7, 1796 |
| Image1: | Official Presidential portrait of John Adams (by John Trumbull, circa 1792).jpg |
| Nominee1: | John Adams |
| Party1: | Federalist Party (United States) |
| Home State1: | Massachusetts |
| Running Mate1: | Thomas Pinckney |
| Electoral Vote1: | 4 |
| Percentage1: | 100.00% |
| President | |
| Before Election: | George Washington |
| Before Party: | Independent (politician) |
| After Election: | John Adams |
| After Party: | Federalist Party (United States) |
The 1796 United States presidential election in Rhode Island took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.
During this election, Rhode Island cast its 4 electoral votes for John Adams.[1]
| 1796 United States presidential election in Rhode Island[2] [3] | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | ||
| Independent | George Washington (incumbent) | — | — | 4 | ||
| Federalist | John Adams | — | — | 4 | ||
| Totals | — | — | 8 | |||