1796 United States presidential election in New Hampshire explained

Election Name:	1796 United States presidential election in New Hampshire
Country:	New Hampshire
Type:	presidential
Previous Election:	1792 United States presidential election in New Hampshire
Previous Year:	1792
Next Election:	1800 United States presidential election in New Hampshire
Next Year:	1800
Election Date:	November 4 – December 7, 1796
Image1:	File:Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg
Nominee1:	John Adams
Party1:	Federalist Party (United States)
Home State1:	Massachusetts
Running Mate1:	Thomas Pinckney
Electoral Vote1:	6
Popular Vote1:	3,265
Percentage1:	89.3%
Nominee2:	Thomas Jefferson
Party2:	Democratic-Republican Party (United States)
Home State2:	Virginia
Running Mate2:	Aaron Burr
Popular Vote2:	393
Percentage2:	10.7%
President
Before Election:	George Washington
Before Party:	Independent politician
After Election:	John Adams
After Party:	Federalist Party

The 1796 United States presidential election in New Hampshire took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election to elect the President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for Federalist candidate and Vice President John Adams, over the Democratic-Republican candidate and Secretary of State Thomas Jefferson by a total of 78.6% margin of the popular vote, making this as one of the most voted for a presidential candidate in presidential voting history of the state of New Hampshire.

Results

1796 United States presidential election in New Hampshire^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Federalist	John Adams	3,265	89.3%	6
	Democratic-Republican	Thomas Jefferson	393	10.7%
Totals			3,658	100.0%	6