Election Name: | 1792 United States presidential election in Virginia |
Country: | Virginia |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1788–89 United States presidential election in Virginia |
Previous Year: | 1788–89 |
Next Election: | 1796 United States presidential election in Virginia |
Next Year: | 1796 |
Election Date: | November 2 – December 5, 1792 |
Image1: | Gilbert Stuart Williamstown Portrait of George Washington.jpg |
Nominee1: | George Washington |
Party1: | Independent (politician) |
Home State1: | Virginia |
Electoral Vote1: | 21 |
Popular Vote1: | 962 |
President | |
Before Election: | George Washington |
After Election: | George Washington |
Before Party: | Independent (politician) |
After Party: | Independent (politician) |
Percentage1: | 100% |
The 1792 United States presidential election in Virginia took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. Virginia's 21 electors each cast one vote for the incumbent, George Washington, and one vote for John Adams, the incumbent Vice President.[1]
Virginia unanimously voted for independent candidate and incumbent president, George Washington. The total vote is composed of 962 for Democratic-Republican electors, all of whom were supportive of Washington and George Clinton.[2] The totals for Virginia appears to be incomplete.
Virginia was divided into 21 electoral districts.
1792 United States presidential election in Virginia | |||||||
---|---|---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |||
Independent | George Washington | 962 | 100% | 21 | |||
Totals | 962 | 100% | 21 | ||||