See main article: 1792 United States presidential election.
| Election Name: | 1792 United States presidential election in Rhode Island |
| Country: | Rhode Island |
| Flag Year: | 1778 |
| Type: | presidential |
| Ongoing: | no |
| Next Election: | 1796 United States presidential election in Rhode Island |
| Next Year: | 1796 |
| Election Date: | November 2 – December 5, 1792 |
| Image1: | Gilbert Stuart Williamstown Portrait of George Washington.jpg |
| Nominee1: | George Washington |
| Party1: | Independent (politician) |
| Running Mate1: | George Clinton |
| Home State1: | Virginia |
| Electoral Vote1: | 4 |
| Percentage1: | 100.00% |
| President | |
| Before Election: | George Washington |
| Before Party: | Independent (politician) |
| After Election: | George Washington |
| After Party: | Independent (politician) |
The 1792 United States presidential election in Rhode Island took place as part of the 1792 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for President and Vice President.
Rhode Island unanimously voted for the incumbent Independent President George Washington.
| 1792 United States presidential election in Rhode Island[1] | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | ||
| Independent | George Washington (incumbent) | — | — | 4 | ||
| Federalist | John Adams | — | — | 4 | ||
| Totals | — | — | 8 | |||