1792 United States presidential election in North Carolina explained

See main article: 1792 United States presidential election.

Election Name:1792 United States presidential election in North Carolina
Type:presidential
Ongoing:no
Next Election:1796 United States presidential election in North Carolina
Next Year:1796
Election Date:November 2 - December 5, 1792
Image1:Gilbert Stuart Williamstown Portrait of George Washington.jpg
Nominee1:George Washington
Party1:Independent (politician)
Home State1:Virginia
Electoral Vote1:12
Percentage1:100.00%
Percentage2:
President
Before Election:George Washington
Before Party:Independent (politician)
After Election:George Washington
After Party:Independent (politician)

The 1792 United States presidential election in North Carolina was held between November 2 – December 5, 1792, as part of the 1792 United States presidential election. 12 members of the Electoral College were allocated to the presidential candidates.

Incumbent Independent President George Washington won and carried the state. This was also the first presidential election in the state of North Carolina.[1]

Background

North Carolina did not participate in the 1788–89 United States presidential election, as it did not ratify the Constitution of the United States until months after the end of that election and after George Washington had assumed office as President of the United States to become the 12th state.[2]

Results

1792 United States presidential election in Virginia[3]
PartyCandidateElectoral votes
IndependentGeorge Washington12
Totals12

See also

References

  1. Web site: US President and NC Governor NCSBE . 2024-05-19 . www.ncsbe.gov.
  2. News: Glass . Andrew . November 21, 2017 . North Carolina ratifies Constitution, Nov. 21, 1789 . 2024-05-19 . Politico.
  3. Web site: Dave Leip's Atlas of U.S. Presidential Elections . 2024-05-19 . uselectionatlas.org.