1792 United States presidential election in New York explained

See main article: 1792 United States presidential election.

Election Name:1792 United States presidential election in New York
Country:New York
Flag Year:1778
Type:presidential
Ongoing:no
Next Election:1796 United States presidential election in New York
Next Year:1796
Election Date:November 2 – December 5, 1792
Image1:Gilbert Stuart Williamstown Portrait of George Washington.jpg
Nominee1:George Washington
Party1:Independent (politician)
Running Mate1:George Clinton
Home State1:Virginia
Electoral Vote1:12
Percentage1:100.00%
President
Before Election:George Washington
Before Party:Independent (politician)
After Election:George Washington
After Party:Independent (politician)

The 1792 United States presidential election in New York took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The New York State Legislature chose 12 members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast 2 votes for president.

New York's 12 electors each cast one vote for incumbent George Washington and one vote for George Clinton in the state's first presidential election.[1] (Although the state had ratified the Constitution to become the eleventh state on July 26, 1788, it did not participate in the first presidential election in 1789 due to the state legislature's being deadlocked.)

See also

Notes and References

  1. https://uselectionatlas.org/RESULTS/ 1792 Presidential Electoral Vote Count