See main article: 1792 United States presidential election.
| Election Name: | 1792 United States presidential election in New Jersey |
| Country: | New Jersey |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1788–89 United States presidential election in New Jersey |
| Previous Year: | 1788–89 |
| Next Election: | 1796 United States presidential election in New Jersey |
| Next Year: | 1796 |
| Election Date: | November 2 - December 5, 1792 |
| Image1: | Gilbert Stuart Williamstown Portrait of George Washington.jpg |
| Nominee1: | George Washington |
| Party1: | Independent (politician) |
| Home State1: | Virginia |
| Electoral Vote1: | 7 |
| Percentage1: | 100.00% |
| Nominee2: | John Adams |
| Party2: | Federalist Party |
| Home State2: | Massachusetts |
| Electoral Vote2: | 7 |
| Percentage2: | – |
| President | |
| Before Election: | George Washington |
| Before Party: | Independent (politician) |
| After Election: | George Washington |
| After Party: | Independent (politician) |
The 1792 United States presidential election in New Jersey took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose seven members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.
New Jersey's seven electors each cast one vote for incumbent George Washington and one vote for incumbent Vice President John Adams.[1]