See main article: 1792 United States presidential election.
Election Name: | 1792 United States presidential election in Delaware |
Country: | Delaware |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1788–89 United States presidential election in Delaware |
Previous Year: | 1788–89 |
Next Election: | 1796 United States presidential election in Delaware |
Next Year: | 1796 |
Election Date: | November 2 – December 5, 1792 |
Image1: | Gilbert Stuart Williamstown Portrait of George Washington.jpg |
Nominee1: | George Washington |
Party1: | Independent (politician) |
Home State1: | Virginia |
Electoral Vote1: | 3 |
Percentage1: | 100.00% |
Nominee2: | John Adams |
Party2: | Federalist Party |
Home State2: | Massachusetts |
Electoral Vote2: | 3 |
Percentage2: | – |
President | |
Before Election: | George Washington |
After Election: | George Washington |
Before Party: | Independent (politician) |
After Party: | Independent (politician) |
The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose three members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.
Delaware's three electors each cast one vote for the incumbent, George Washington, and one vote for John Adams, the incumbent Vice President.[1]
United States presidential election in Delaware, 1792 | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Independent | George Washington (incumbent) | 100.00% | 3 | ||
Totals | 100.00% | 3 | |||