See main article: 1792 United States presidential election.
| Election Name: | 1792 United States presidential election in Connecticut |
| Country: | Connecticut |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1788–89 United States presidential election in Connecticut |
| Previous Year: | 1788–89 |
| Next Election: | 1796 United States presidential election in Connecticut |
| Next Year: | 1796 |
| Election Date: | November 2 - December 5, 1792 |
| Image1: | Gilbert Stuart Williamstown Portrait of George Washington.jpg |
| Nominee1: | George Washington |
| Party1: | Independent (politician) |
| Home State1: | Virginia |
| Electoral Vote1: | 9 |
| Percentage1: | 100.00% |
| Nominee2: | John Adams |
| Party2: | Federalist Party |
| Home State2: | Massachusetts |
| Electoral Vote2: | 9 |
| Percentage2: | – |
| President | |
| Before Election: | George Washington |
| Before Party: | Independent (politician) |
| After Election: | George Washington |
| After Party: | Independent (politician) |
The 1792 United States presidential election in Connecticut took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose nine members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.
Connecticut's nine electors each cast one vote for incumbent George Washington and one for incumbent Vice President John Adams.[1]