| Election Name: | 1790 Massachusetts gubernatorial election |
| Country: | Massachusetts |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1789 Massachusetts gubernatorial election |
| Previous Year: | 1789 |
| Next Election: | 1791 Massachusetts gubernatorial election |
| Next Year: | 1791 |
| Election Date: | 5 April 1790 |
| Nominee1: | John Hancock |
| Party1: | Nonpartisan politician |
| Popular Vote1: | 14,360 |
| Percentage1: | 86.53% |
| Nominee2: | James Bowdoin |
| Party2: | Nonpartisan politician |
| Popular Vote2: | 1,880 |
| Percentage2: | 11.33% |
| Governor | |
| Before Election: | John Hancock |
| Before Party: | Nonpartisan politician |
| After Election: | John Hancock |
| After Party: | Nonpartisan politician |
The 1790 Massachusetts gubernatorial election was held on 5 April 1790 in order to elect the Governor of Massachusetts. Incumbent Governor John Hancock won re-election against former Governor James Bowdoin.[1]
On election day, 5 April 1790, incumbent Governor John Hancock won re-election by a margin of 12,480 votes against his opponent former Governor James Bowdoin. Hancock was sworn in for his ninth overall term on 30 May 1790.[2]