| Election Name: | 1789 Connecticut gubernatorial election |
| Country: | Connecticut |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1788 Connecticut gubernatorial election |
| Previous Year: | 1788 |
| Next Election: | 1790 Connecticut gubernatorial election |
| Next Year: | 1790 |
| Election Date: | 9 April 1789 |
| Nominee1: | Samuel Huntington |
| Party1: | Federalist Party (United States) |
| Popular Vote1: | 1 |
| Percentage1: | 100.00% |
| Governor | |
| Before Election: | Samuel Huntington |
| Before Party: | Federalist Party (United States) |
| After Election: | Samuel Huntington |
| After Party: | Federalist Party (United States) |
The 1789 Connecticut gubernatorial election was held on 9 April 1789 in order to elect the Governor of Connecticut. Incumbent Federalist Governor of Connecticut Samuel Huntington won re-election as he ran unopposed.[1]
On election day, 9 April 1789, Federalist nominee Samuel Huntington easily won re-election as he ran unopposed. Huntington was sworn in for his fourth term on 11 May 1789.[2]