See main article: 1788–89 United States presidential election.
| Election Name: | 1788–89 United States presidential election in New Hampshire |
| Country: | New Hampshire |
| Type: | presidential |
| Ongoing: | no |
| Next Election: | 1792 United States presidential election in New Hampshire |
| Next Year: | 1792 |
| Image1: | Gilbert Stuart Williamstown Portrait of George Washington.jpg |
| Nominee1: | George Washington |
| Party1: | Independent (politician) |
| Home State1: | Virginia |
| Electoral Vote1: | 5 |
| Popular Vote1: | 1,759 |
| Percentage1: | 100.00% |
| Nominee2: | John Adams |
| Party2: | Federalist Party |
| Home State2: | Massachusetts |
| Electoral Vote2: | 5 |
| Popular Vote2: | – |
| Percentage2: | – |
| President | |
| Before Election: | Office established |
| After Election: | George Washington |
| After Party: | Independent (United States) |
The 1788–89 United States presidential election in New Hampshire took place on January 7, 1789, as part of the 1788–89 United States presidential election to elect the first President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire unanimously voted for independent candidate and commander-in-chief of the Continental Army, George Washington. The total vote was composed of 1,759 for Federalist electors, all of whom were supportive of Washington.[1] Several candidates of unknown affiliation also received votes.
Voters voted for electors on December 15, 1788, through a general ticket. As no elector candidate received the "requisite number for a choice," the election went to the legislature,[2] which selected the five best-performing elector candidates from the top ten on January 7, 1789.[3]
| 1788-1789 United States presidential election in New Hampshire | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Independent | George Washington | 1,759 | 100.00% | 5 | |
| Totals | 1,759 | 100.00% | 5 | ||