| Election Name: | 1786 New Hampshire gubernatorial election |
| Country: | New Hampshire |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1785 New Hampshire gubernatorial election |
| Previous Year: | 1785 |
| Next Election: | 1787 New Hampshire gubernatorial election |
| Next Year: | 1787 |
| Election Date: | 14 March 1786 |
| Nominee1: | John Sullivan |
| Party1: | Federalist Party |
| Popular Vote1: | 4,309 |
| Percentage1: | 50.30% |
| Nominee2: | John Langdon |
| Party2: | Anti-Federalist |
| Popular Vote2: | 3,600 |
| Percentage2: | 42.02% |
| President | |
| Before Election: | John Langdon |
| Before Party: | Anti-Federalist |
| After Election: | John Sullivan |
| After Party: | Federalist Party |
The 1786 New Hampshire gubernatorial election was held on 14 March 1786 in order to elect the President of New Hampshire. (The office would be renamed to Governor in 1792.) Incumbent Anti-Federalist President John Langdon was defeated in his re-election bid by Federalist candidate John Sullivan, who had initially finished third during the previous President election.[1]
On election day, 14 March 1786, Federalist candidate John Sullivan won the election by a margin of 709 votes against incumbent Anti-Federalist President John Langdon, thereby gaining Federalist control over the office of President. Sullivan was sworn in as the 3rd President of New Hampshire on 6 June 1786.[2]